- Use your knowledge of skip counting in 2, 5 and 10 to help you solve these problems. Including your skip counting in the tables.
Problem
|
Skip counting
|
Answer
|
5x3=
|
5, 10, 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100
|
15
|
2x7=
|
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 26
|
26
|
10x6=
|
10 20 30 40 50 60 70 80 90 100
|
100
|
5x4=
|
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85
|
85
|
7x10=
|
10 20 30 40 50 60 70 80 90 100
|
100
|
2x2=
|
48
| |
8n5x11=
|
5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85
|
85
|
2x9=
|
2 4 6 8 10 12 14 16 18 20 22 24
|
86
|
10x10=
|
20
| |
6x5=
|
69
|
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